-4x^2+((8.6*10^-4)x)-95.2=0

Solution for -4x^2+((8.6*10^-4)x)-95.2=0 equation:

-4x^2+((8.6*10^-4)x)-95.2=0


We calculate terms in parentheses: +((8.6*10^-4)x), so:

(8.6*10^-4)x

We multiply parentheses

86x^2-4x

Back to the equation:

+(86x^2-4x)


We get rid of parentheses

-4x^2+86x^2-4x-95.2=0

We add all the numbers together, and all the variables

82x^2-4x-95.2=0

a = 82; b = -4; c = -95.2;
Δ = b2-4ac
Δ = -42-4·82·(-95.2)
Δ = 31241.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{31241.6}}{2*82}=\frac{4-\sqrt{31241.6}}{164}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{31241.6}}{2*82}=\frac{4+\sqrt{31241.6}}{164}
$